二次根式计算题,分母有理化X/(200+X) =根号3/3

问题描述:

二次根式计算题,分母有理化
X/(200+X) =根号3/3

过程:
根号3 *(200+X)=3X
200*根号3=(3-根号3)* X
X=200*根号3/(3-根号3)

X/(200+X) =根号3/3
1-X/(200+X) =1-根号3/3
200/(200+X) =1-根号3/3
(200+X) =200/(1-根号3/3 )
x=200-200/(1-根号3/3 )=200-600/(3-根号3)=200-100*(3+根号3)=-100-100*根号3