已知log3(2)=a,则用a表示log6[24^(1/2)]=
问题描述：
已知log3(2)=a,则用a表示log6[24^(1/2)]=
答
log6[24^(1/2)]=(1/2)[log6(6*4)]
=(1/2)[1+log6(4)]=(1/2)[1+2a/(1+a)]
=1/2+a/(1+a)
log6(4)=log3(4)/log3(6)=2log3(2)/[log3(3)+log3(2)]=2a/(1+a)