1/7【1/5(x+2/3 + 4)+6】+8=9

问题描述:

1/7【1/5(x+2/3 + 4)+6】+8=9

1/3

1/7【1/5(x+2/3 + 4)+6】+8=9
两边同时乘以7得
1/5(x+2/3 + 4)+6 +56=63
1/5x+2/15+4/5=1
两边在同时乘以15得
3x+2+12=15
移项得
3x=1
x=1/3

1/7【1/5(x+2/3 + 4)+6】+8=9
1/7【1/5(x+2/3 + 4)+6】=9-8
1/7【1/5(x+2/3 + 4)+6】=1
1/5(x+2/3 + 4)+6=7
1/5(x+2/3 + 4)=7-6
1/5(x+2/3 + 4)=1
x+2/3+4=5
x+2/3=1
x+2=3
x=1

1/7【1/5(x+2/3 + 4)+6】+8=9
1/7【1/5(x+2/3 + 4)+6】=1
1/5(x+2/3 + 4)+6=7
1/5(x+2/3 + 4)=1
x+2/3 + 4=5
x+2/3 =1
x=1/3