√3sinωxcosωx+cos^2ωx-1/2
问题描述:
√3sinωxcosωx+cos^2ωx-1/2
答
√3sinωxcosωx+cos^2ωx-1/2
=(√3/2)sin(2ωx)+[2cos^2(ωx)-1]/2
=sin(2ωx)*cos(π/6)+cos(2ωx)sin(π/6)
=sin(2ωx+π/6).