sin(x+派/3)sin(x+11派/6)=1/2定义域是 ：负派 到 派/2
问题描述：
sin(x+派/3)sin(x+11派/6)=1/2定义域是 ：负派 到 派/2
sin(x+派/3)sin(x+11派/6)=1/2
定义域是 ：负派 到 派/2
摆脱了~
答
sin(x+π/3)sin(x+11π/6)=1/2则有：sin(x+π/3)sin[(x-π/6)+2π]=1/2sin(x+π/3)sin(x-π/6)=1/2 -----(1)由于：sin(x+π/3)=sinxcos(π/3)+sin(π/3)cosx=(1/2)sinx+(√3/2)cosxsin(x-π/6)=sinxcos(π/6)-sin(π...