化简[sin(2π-α)cos(π+α)cos(π/2+α)cos(11π/2-α)]/[cos(π-α)sin(π+α)sin(-π-α)sin[(...

问题描述:

化简[sin(2π-α)cos(π+α)cos(π/2+α)cos(11π/2-α)]/[cos(π-α)sin(π+α)sin(-π-α)sin[(...
化简[sin(2π-α)cos(π+α)cos(π/2+α)cos(11π/2-α)]/[cos(π-α)sin(π+α)sin(-π-α)sin[(9π/2)+α]]

-sinα*-cosα*-sinα*sinα/-cosα*-sinα*sinα*-cosα
=tanα