a1x+b1y=c1,a2x+b2y=c2的解是x=3,y=4,解方程组3A1X+2B1Y=5C1,3A2X=2B2Y=5C2
问题描述:
a1x+b1y=c1,a2x+b2y=c2的解是x=3,y=4,解方程组3A1X+2B1Y=5C1,3A2X=2B2Y=5C2
答
将方程组3a1x+2b1y=5c1,3a2x+2b2y=5c2变形,得
a1(3x/5)+b1(2y/5)=c1
a2(3x/5)+b2(2y/5)=c2
与已知方程组对比,得
3x/5=3,x=5
2y/5=4,y=10
x=5,y=10