(x+y)(x²+y²)(x-y)(x的四次方+y的四次方)
问题描述:
(x+y)(x²+y²)(x-y)(x的四次方+y的四次方)
答
(x+y)(x²+y²)(x-y)(x的四次方+y的四次方)
=(x2-y^2)(x^2+y^2)(x^4+y^4)
=(x^4-y^4))(x^4+y^4)
=x^8-y^8
答
(x+y)(x²+y²)(x-y)(x的四次方+y的四次方)
=(x+y)(x-y))(x²+y²)(x^4+y^4)
=(x^2-y^2)(x^2+y^2)(x^4+y^4)
=(x^4-y^4)(x^4+y^4)
=x^8-y^8
答
原式=(x+y)(x-y)(x^2+y^2)(x^4+y^4)
=(x^2-y^2)(x^2+y^2)(x^4+y^4)
=(x^4-y^4)(x^4+y^4)
=x^8-y^8