等差数列{An}的前n项和为40,前2n项和为120,则前3n项和为_____
问题描述:
等差数列{An}的前n项和为40,前2n项和为120,则前3n项和为_____
答
Sn,S2n-Sn,S3n-S2n是等差数列
即40,120-40,S3n-120是等差数列
2×80=40+S3n-120
S3n=240