y=cos (x平方) 求 y,和y,y=cos平方x,求y,和y,

问题描述:

y=cos (x平方) 求 y,和y,y=cos平方x,求y,和y,

y = cos x²y' = - sinx² * 2x = - 2x sinx²y'' = - 2 sinx² + (-2x)*cosx² *2x = - 2sinx² - 4x² cosx²y = cos²x = (1+cos2x)/2y' = - sin2xy'' = - 2cos2x