(3√3-√12+√6)除以2√3

问题描述:

(3√3-√12+√6)除以2√3

(3√3-√12+√6)除以2√3
=(3√3-2√3+√6)÷2√3
=1/2+√6/2

(3√3-√12+√6)/2√3=3/2 -1+√2/2=1/2+√2/2=(1+√2)/2

(3√3-√12+√6)除以2√3
=3√3÷2√3-√12÷2√3+√6÷2√3
=3/2-1+√2/2
=1/2+√2/2
=(1+√2)/2