证明(x+1)(X+3)(x+5)(x+7)+15=(X"+8x)"+22(x"+8x)+120
问题描述:
证明(x+1)(X+3)(x+5)(x+7)+15=(X"+8x)"+22(x"+8x)+120
答
(x+1)(X+3)(x+5)(x+7)+15
=(x+1)(x+7)(x+5)(x+3)+15
=(X"+8x+7)(X"+8x+15)
=(X"+8x)"+22(x"+8x)+105+15
=(X"+8x)"+22(x"+8x)+120
答
证明:(x+1)(x+3)(x+5)(x+7)+15=[(x+1)(x+7)]*[(x+3)(x+5)]+15=[(x^2+8x)+7)]*[(x^2+8x)+15)]+15=(x^2+8x)^2+15(x^2+8x)+7(x^2+8x)+105+15=(x^2+8x)^2+22(x^2+8x)+120