sin14/3π+cos（-23π/4）+tan（-25π/3）=?
问题描述：
sin14/3π+cos（-23π/4）+tan（-25π/3）=?
答
=sin(2/3π)+cos(1/4π)+tan(2/3π)=3根号3/2-根号2/2
答
答题而已，。，。
答
原式=sin(4π+2/3π)+cos(-6π+π/4)+tan(-8π-π/3)
=sin(2π/3)+cos(π/4)-tan(π/3)
=√3/2+√2/2-√3
=(-√3+√2)/2