把x^2+7/(x+3)(x-1)^2分解成部分分式
问题描述:
把x^2+7/(x+3)(x-1)^2分解成部分分式
答
(x²+7)/[(x+3)(x-1)²]
=(x²-2x+1+2x+6)/[(x+3)(x-1)²]
=[(x-1)²+2(x+3)]/[(x+3)(x-1)²]
=1/(x+3)+2/(x-1)²