化简求职:((x^2-16/(x^2+8x+16)+x/(x-4))÷1/(x^2-16),其实x=根号2+1
问题描述：
化简求职:((x^2-16/(x^2+8x+16)+x/(x-4))÷1/(x^2-16),其实x=根号2+1
计算根号27+1/（2+根号3）-（根号3/2）的0次方
答
((x^2-16/(x^2+8x+16)+x/(x-4))÷1/(x^2-16)
=（x-4)(x+4)/(x+4)²+x/(x-4)*(x-4)(x+4)
=(x-4)/(x+4)+x/(x+4)
=(2x-4)/(x+4)
=(2√2+2-4)/(√2+1+4)
=2(√2-1)(√2-5）/(√2+5)(√2-5)
=2(2-5√2-√2+5)/(2-25）
=2（7-6√2）/-23
=(12√2-14)/23
根号27+1/（2+根号3）-（根号3/2）的0次方
=3√3+(2-√3)/(2-√3)(2+√3)-1
=3√3+2-√3-1
=2√3+1