计算:(x-3/x^2+6x+9)+(x/9-x^2,)并求当x=2时原式的值
问题描述:
计算:(x-3/x^2+6x+9)+(x/9-x^2,)并求当x=2时原式的值
答
原式=(x-3)/(x+3)+x/(9-x) =(2-3)/(2+3)+2/(9-2) =-1/25+2/5 =9/25
计算:(x-3/x^2+6x+9)+(x/9-x^2,)并求当x=2时原式的值
原式=(x-3)/(x+3)+x/(9-x) =(2-3)/(2+3)+2/(9-2) =-1/25+2/5 =9/25