函数y=cos(x+π/3)(x∈【π/6,5π/12】)的最小值是

问题描述:

函数y=cos(x+π/3)(x∈【π/6,5π/12】)的最小值是

x∈[π/6,5π/12]
x+(π/3)∈[π/2,3π/4]
y=cos(x+π/3)∈[-(1/√2),0]