f(x)=sin^2-sin[2x-(π/6)]的值域过程
问题描述：
f(x)=sin^2-sin[2x-(π/6)]的值域过程
答
f(x)=(1-cos2x)/2-(sin2xcosπ/6-cos2xsinπ/6)
=1/2-1/2*cos2x-sin2xcosπ/6+1/2*cos2x
=-(√3/2)sin2x+1/2
-1-√3/2加上1/2
所以值域[(-√3+1)/2,(√3+1)/2]