(1)计算:根号下8-2×根号下2/2+(根号下3-1)º (2)因式分解:a³b-ab
问题描述:
(1)计算:根号下8-2×根号下2/2+(根号下3-1)º (2)因式分解:a³b-ab
会是会写,只是不知道答案对不对,顺带过程,拜托啦
答
(1)计算:根号下8-2×根号下2/2+(根号下3-1)º
=2√2-√2+1
=√2+1
(2)因式分a³b-ab
=ab(a²-1)
=ab(a-1)(a+1)