已知方程4x^2-4xy+2y^2+2y+1=0,求x,y的值!
问题描述：
已知方程4x^2-4xy+2y^2+2y+1=0,求x,y的值!
各位大哥十万火急啊,请速速解答吧!
答
4x^2-4xy+2y^2+2y+1=0
(4x^2-4xy+y^2)+(y^2+2y+1)=0
(2x-y)^2+(y+1)^2=0
2x-y=0,y+1=0
x=-1/2,y=-1