函数2sin(2x+π/3) ,若对任意x∈[0,5π/12],使不等式f(x)<m恒成立,求函数m的取值范围.
问题描述:
函数2sin(2x+π/3) ,若对任意x∈[0,5π/12],使不等式f(x)<m恒成立,求函数m的取值范围.
一定要有过程呀.
答
x∈[0,5π/12]
π/3≤2x+π/3≤7π/6
-1/2≤sin(2x+π/3)≤1
-1≤2sin(2x+π/3)≤2
2sin(2x+π/3)2