=√3sin2x+cos2x+a =2sin(2x+π/6)+a 请问怎么推的
问题描述:
=√3sin2x+cos2x+a =2sin(2x+π/6)+a 请问怎么推的
答
=√3sin2x+cos2x+a
=2(√3/2×sin2x+1/2×cos2x)+a
=2(cosπ/6×sin2x+cos2xsinπ/6)+a
=2sin(2x+π/6)+a