已知多项式x2-(3k-1)xy-3y2+3mx2-8中不含xy和x2项,求8k+123m+2的值.

问题描述:

已知多项式x2-(3k-1)xy-3y2+3mx2-8中不含xy和x2项,求

8k+1
23m+2
的值.

x2-(3k-1)xy-3y2+3mx2-8,
=(1+3m)x2-(3k-1)xy-3y2-8,
∵不含xy和x2项,
∴1+3m=0,-(3k-1)=0.
3m=-1,k=

1
3

8k+1
23m+2
8
1
3
+1
2−1+2
24
2
=8

故答案为:8.