已知多项式x2-(3k-1)xy-3y2+3mx2-8中不含xy和x2项,求8k+123m+2的值.
问题描述:
已知多项式x2-(3k-1)xy-3y2+3mx2-8中不含xy和x2项,求
的值. 8k+1 23m+2
答
x2-(3k-1)xy-3y2+3mx2-8,
=(1+3m)x2-(3k-1)xy-3y2-8,
∵不含xy和x2项,
∴1+3m=0,-(3k-1)=0.
3m=-1,k=
.1 3
∴
=8k+1 23m+2
=8
+11 3 2−1+2
=8.24 2
故答案为:8.