已知x=1/2,求x²-1/x²-2x+1+x²-2x/x-2的值
问题描述：
已知x=1/2,求x²-1/x²-2x+1+x²-2x/x-2的值
答
x=1/2
(x²-1)/(x²-2x+1)+(x²-2x)/(x-2)
=(x-1)(x+1)/(x-1)²+(x-2)x/(x-2)
=(x+1)/(x-1)+x
=[3/2]/[1/2]+1/2
=3+1/2
=7/2