化简：根号(1-2sin100°cos280°)/{cos370°-根号[1-cos^2(170°)]}
问题描述：
化简：根号(1-2sin100°cos280°)/{cos370°-根号[1-cos^2(170°)]}
答
sinαcosβ = [sin(α+β)+sin(α-β)]/2所以sin100cos280 = [sin(α+)+sin(α-β)]/2=sin20/2根号(1-2sin100°cos280°)=根号(1-sin20)=根号(1-2sin10cos10)=cos10-sin10根号[1-cos^2(170°)]=sin(170°)=cos(80°)...