3a(m-n)的3次方-a(n-m)的平方+a(n-m)

问题描述:

3a(m-n)的3次方-a(n-m)的平方+a(n-m)

原式=3a(m-n)³-a(n-m)²+a(n-m)
=a[3(m-n)³-(m-n)²-(m-n)]
=a(m-n)[3(m-n)²-(m-n)-1]

3a(m-n)³-a(n-m)²+a(n-m)
=3a(m-n)³-a(m-n)²-a(m-n)
=a(m-n)[3(m-n)²-m+n-1]
=a(m-n)(3m²+3n²-6mn-m+n-1)

=3a(m-n)³-a(m-n)²-a(m-n)
=a(m-n)[3(m-n)²-(m-n)-1]
=a(m-n)(3m²-6mn+3n²-m+n-1)