求行列式b a a a 的值 a b a a a a b a a a a b
问题描述:
求行列式b a a a 的值 a b a a a a b a a a a b
答
baaaabaaaabaaaabb+3a b+3a b+3a b+3ar1+r2+r3+r4 a b a a========== a a b aa a a b1 1 1 1=(b+3a) a b a aa a b aa a a bc2-c1 1 0 0 0 c3-c1 a b-a 0 0====(b+3a) a 0 b-a 0c4-c1 a 0 0 b-a=(b+3a)(b-a)³