(x+1)/2-(4y+3)/3=-7,(x+10)/5-(3y+1)/2=-4
问题描述:
(x+1)/2-(4y+3)/3=-7,(x+10)/5-(3y+1)/2=-4
答
您好:(x+1)/2-(4y+3)/3=-7两边乘63(x+1)-2(4y+3)=-423x+3-8y-6=-423x-8y=-396x-16y=-78 (x+10)/5-(3y+1)/2=-4 两边乘102x+20-15y-5=-42x-15y=-196x-45y=-57 两式相减45y-16y=-78+5729y=-21y=-21/29 2x=15y-19...