f(x)=6x^4-x^2+1求x=2的值
问题描述:
f(x)=6x^4-x^2+1求x=2的值
答
f(2)=6*x^4-2^2+1
=96-4+1
=93
f(x)=6x^4-x^2+1求x=2的值
f(2)=6*x^4-2^2+1
=96-4+1
=93