若x+y+z=2,x2-(y+z)2=8,求x-y-z= x2为X的平方

问题描述:

若x+y+z=2,x2-(y+z)2=8,求x-y-z= x2为X的平方

x2-(y+z)2
=(x+y+z)(x-y-z)
=8
x+y+z=2
所以x-y-z=8÷2=4