解下列方程:5(x^2-x)=3(x^2+x) (x-2)^2=(2x+3)^2 (x-2)(x-3)=12 2x+6=(x+3)^2 2y^2+4y=y+2

问题描述:

解下列方程:5(x^2-x)=3(x^2+x) (x-2)^2=(2x+3)^2 (x-2)(x-3)=12 2x+6=(x+3)^2 2y^2+4y=y+2

5(x^2-x)=3(x^2+x)5x²-5x=3x²+3x2x²-8x=02x(x-4)=0x=0 x=4(x-2)^2=(2x+3)^2x-2=2x+3 x-2=-2x-3x=-5 x=-1/3(x-2)(x-3)=12 x²-5x-6=0(x-6)(x+1)=0x=6 x=-12x+6=(x+3)^2x²+4x+3=0(x+1)(x+3)=0...