f(x/x+2)=f(x+1)/x+3,则求f(5)的值

问题描述:

f(x/x+2)=f(x+1)/x+3,则求f(5)的值

当x = 4 则f(2/3) = f(5)/7当x = -1/3 则f(-1/5) = f(2/3) / (8 / 3)当X = -6/5 则f(-3/2) = f(-1/5)/(9/5)当x = -5/2 则f(5) = f(-3/2)/(1/2)则循环一遍后发现f(5) = a*f(5)(a为常数,我就不算了,就上面的相乘),也...等号后边是[f(x+1)/x]+3, 这是选择题,选项有 2/25-2/254/25-4/25抱歉算错数了,最后f(5)=-4/25算的方法就是像上面一样循环代数,不过要简单一点的话就把x = x-1使得后面f(x+1)变成f(x)然后就是计算与迭代