y=1-[sin(x+π/3)]^2的最小正周期是?
问题描述:
y=1-[sin(x+π/3)]^2的最小正周期是?
答
y=1-[sin(x+π/3)]^2=1-[1-cos(2x+2π/3)]/2=cos(2x+2π/3)/2+1/2
T=π