求函数y=sin(-2x+π/4)x属于[0,π]的单调递增区间
问题描述:
求函数y=sin(-2x+π/4)x属于[0,π]的单调递增区间
答
函数y=sin(-2x+π/4)
=-sin(2x-π/4)
y=sin(2x-π/4)的减区间为
2kπ+π/2