设向量a=(cosx,sinx),向量b=(根号3,-1)
问题描述：
设向量a=(cosx,sinx),向量b=(根号3,-1)
试确定|2a-b|的最大值以及相应x得取值.
答
①f(x)=cosx(sinx √3cosx) (cosx-√3sinx)sinx =2sinxcosx √3cos^2 x-√3sin^2 x =sin2x √3cos2x =2sin(2x π/3) ②x∈[-π/2,π/2],则2x π/3∈[-2π/3,4π/3] 则2x π/3∈[-π/2,π/2]时,即x∈[-5π/12,π/12]...