分解因数：x的四次方-4x+3
问题描述：
分解因数：x的四次方-4x+3
急
答
x^4-4x+3=x^4-1-4x+4=(x^2+1)(x^2-1)-4(x-1)=(x^2+1)(x+1)(x-1)-4(x-1)=(x-1)(x^3+x^2+x+1-4)=(x-1)(x^3+x^2+x-3)=(x-1)[(x^3-1)+(x^2-1)+(x-1)]=(x-1)[(x-1)(x^2+x+1)+(x-1)(x+1)+(x-1)]=(x-1)^2[(x^2+x+1)+(x+1)+1...