(1+2xy)^2-(x^2+y^2)^2速求
问题描述：
(1+2xy)^2-(x^2+y^2)^2速求
因式分解
答
原式=[(1+2xy)+(x²+y² )][(1+2xy)-(x² +y² )]=-(x²+y² +2xy+1)(x² +y² -2xy-1) =-(x²+y² +2xy+1)[(x-y)² -1)]=-(x²+y² +2xy+1)[(x-y)+1][(x-y)-1...