(2+1)(2^2+1)(2^4+1)(2^8+1)···(2^64+1)+1
问题描述:
(2+1)(2^2+1)(2^4+1)(2^8+1)···(2^64+1)+1
答
运用平方差公式:(a-b)(a+b)=a²-b²
原式
=(2-1)(2+1)(2²+1)(2^4+1)……(2^64+1)+1
=(2²-1)(2²+1)(2^4+1)……(2^64+1)+1
=(2^4-1)(2^4+1)……(2^64+1)+1
……
=(2^64-1)(2^64+1)+1
=2^128-1+1
=2^128
不懂追问~