(1/4a^3+nb^m-1)^2·(4a^3+nb^m+1)^2

问题描述:

(1/4a^3+nb^m-1)^2·(4a^3+nb^m+1)^2

(1/4a^3+nb^m-1)^2·(4a^3+nb^m+1)^2
=1/16a^6+2nb^2m-2*16a^6+2nb^2m+2
=a^12+4nb^4m