(x的平方-9)÷(x的平方-6x+9)
问题描述:
(x的平方-9)÷(x的平方-6x+9)
答
(x²-9)÷(x²-6x+9)
=(x-3)(x+3)/(x-3)²
=(x+3)/(x-3)
答
(x²-9)÷(x²-6x+9)
=(x+3)(x-3)/(x-3)²
=(x+3)/(x-3)
=(x-3+6)/(x-3)
=1+ 6/(x-3)
答
(x²-9)÷(x²-6x+9)
=[(x+3)(x-3)]/(x-3)²
=(x+3)/(x-3)
明白请采纳,
有新问题请求助,
答
原式=(x+3)(x-3)/(x-3)^2=(x+3)/(x-3)=(x-3+6)/(x-3)=1+ 6/(x-3)
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