已知a与b互为相反数,c与d互为倒数,x=3(a-1)-(a-2b),y=c^2d+d^2-((d/c)+c-1),求(2x+y)/3-(3x-2y)/6的值
问题描述:
已知a与b互为相反数,c与d互为倒数,x=3(a-1)-(a-2b),y=c^2d+d^2-((d/c)+c-1),求(2x+y)/3-(3x-2y)/6的值
答
已知a与b互为相反数,c与d互为倒数,x=3(a-1)-(a-2b),y=c^2d+d^2-((d/c)+c-1),求(2x+y)/3-(3x-2y)/6的值