(1+2)(1+2^2/1)(1+2^4/1)(1+2^8/1)+2^16/1

问题描述:

(1+2)(1+2^2/1)(1+2^4/1)(1+2^8/1)+2^16/1

AC都在x轴
则高是B到x轴距离=|5|=5
面积是5
所以底边AC=5×2÷5=2
4-2=2
4+2=6
所以C是(2,0)或(6,0)
4134153153

(1+2)(1+2^2/1)(1+2^4/1)(1+2^8/1)+2^16/1
=(1+2)(1+2^2/1)(1+2^4/1)(1+2^8/1)(1-2^8/1)/(1-2^8/1)+2^16/1
=(1+2)(1+2^2/1)(1+2^4/1)(1-2^4/1)/(1-2^8/1)+2^16/1
=(1+2)(1+2^2/1)(1-2^2/1)/(1-2^8/1)+2^16/1
=(1+2)(1-2)/(1-2^8/1)+2^16/1
=-3/(1-2^8/1)+2^16/1