已知x、y满足根号下4x-5y+根号下x-y-1=0,则根号下xy-根号下x/y我已知道4x-5y=0,x-y-1=0 解得x=5,y=4 那后面怎么算?

问题描述:

已知x、y满足根号下4x-5y+根号下x-y-1=0,则根号下xy-根号下x/y
我已知道4x-5y=0,x-y-1=0 解得x=5,y=4 那后面怎么算?

=根号下20-根号下5/4=2*根号下5-1/2根号下5=3/2根号下5

√xy-√x/y
=√5·4-√5/4
=2√5-√5/2
=3√5/2