已知3x=2y,求x/y-y/x-x²+y²/xy的值
问题描述:
已知3x=2y,求x/y-y/x-x²+y²/xy的值
答
3x=2y
y/x=3/2
x/y-y/x-(x²+y²)/xy
=x/y-y/x-x²/xy-y²/xy
=x/y-y/x-x/y-y/x
=-2y/x
=-2*3/2
=-3
答
=(x²-y²-x²-y²)/xy
=-2y²/xy
=-2y/x 2y=3x
=-3x/x
=-3