曲线y=(1/5)x^5+3x^2+4x在x=1处的切线的倾斜角是
问题描述:
曲线y=(1/5)x^5+3x^2+4x在x=1处的切线的倾斜角是
答
y=(1/5)x^5+3x^2+4x
y'=x^4+6x+4
x=1时,y'=1+6+4=11
倾斜角为arctan11