求函数的单调区间
问题描述：
求函数的单调区间
y=3sin(∏/3-2x)
答
y=-3sin(2x-π/3)其单调区间与y=3sin(2x-π/3)相反2x-π/3∈[2kπ-π/2,2kπ+π/2],即x∈[kπ-π/12.kπ+5π/12]时,y=-3sin(2x-π/3)单减2x-π/3∈[2kπ+π/2,2kπ+3π/2],即x∈[kπ+5π/12.kπ+11π/12]时,y=-3sin(...