y=asinx+acosx=√2*a(√2/2sinx+√2/2cosx) =√2*a(cosπ/4sinx+cosxsinπ/4) =√2*asin(x+π/4)
问题描述:
y=asinx+acosx=√2*a(√2/2sinx+√2/2cosx) =√2*a(cosπ/4sinx+cosxsinπ/4) =√2*asin(x+π/4)
值域
答
y=asinx+acosx==√2*asin(x+π/4)
当a>0时,y最大值为√2*a,最小值为-√2*a
值域:[-√2*a,√2*a]
当a