若(x+y)2=25,(x-y)2=1,x2+y2的值是_.

问题描述:

若(x+y)2=25,(x-y)2=1,x2+y2的值是______.

∵(x+y)2=25,(x-y)2=1,
∴x2+2xy+y2=25,x2-2xy+y2=1,
两式相加得:2x2+2y2=26,
∴x2+y2=13,
故答案为:13.