求y=log2(-x2+2x+3)
问题描述:
求y=log2(-x2+2x+3)
答
y=log2(-x2+2x+3)
(-x2+2x+3)>0
x^2-2x-3
求y=log2(-x2+2x+3)
y=log2(-x2+2x+3)
(-x2+2x+3)>0
x^2-2x-3