f(x)=[2sin(x+π/3)+sinx]cosx-根号3sin2x,化简
问题描述：
f(x)=[2sin(x+π/3)+sinx]cosx-根号3sin2x,化简
答
f(x)=[2sin(x+π/3)+sinx]cosx-√3sin2x
=[2sinx+√3cosx]cosx-√3sin2x
=sin2x+(√3/2）（1+cos2x)-√3sin2x
=(1-√3）sin2x+(√3/2）cos2x+√3/2
=繁!
请检查题目f(x)=[2sin(x+π/3)+sinx]cosx-根号3sin^2x